Let f x be a real valued function defined on -1-1 and e - x f x -2-0 x - t 4- dt - Then the value of f -0 isA- 1 A- 1B- 1-3C- 3D- 0

The correct option is C 3 e^ xf(x)= 2 + ∫_0^x√(t^4 + 1) dt e^ x(f'(x) f(x)) = √(x^4 + 1)⟶f'(0) = 3 ...

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Property 1

Let f x be a ...

Question

Let f(x) be a real valued function defined on (-1,1) and $e^{- x} f (x) = 2 + \int_{0}^{x} \sqrt{t^{4} + d t}$ . Then the value of $f^{'} (0)$ is

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e^{- x} f (x) = 2 + \int_{0}^{x} \sqrt{t^{4} + 1} d t

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