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Question

Let f(x) be a twice differentiable function and f′′(0)=5, then limx03f(x)4f(3x)+f(9x)x2 is equal to

A
80
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B
100
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C
120
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D
140
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Solution

The correct option is C 120
limx03f(x)4f(3x)+f(9x)x2 (00 form)
Applying L- Hospital's rule
limx03f(x)12f(3x)+9f(9x)2x (00 form)
=limx03f′′(x)36f′′(3x)+81f′′(9x)2
=3f′′(0)36f′′(0)+81f′′(0)2
=24f′′(0)=24(5)=120

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