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Question

Let F(x) be the primitive of 3x+2x9 with respect to x. If F(10)=60, then the value of F(13) is

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Solution

F(x)=3x+2x9dx
Put x9=t2
dx=2t dt
F(x)=(3(t2+9)+2t)2t dt
=2(29+3t2)dt=2(29t+t3)+C
F(x)=2[29x9+(x9)3/2]+C
As F(10)=60, C=0
F(x)=2[29x9+(x9)3/2]
F(13)=2(58+8)=132

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