Question

Let $f\left(x\right)=\{\begin{array}{cc}\sqrt{1+x^2},& x<\sqrt{3}\\ \sqrt{3}x-1,& \sqrt{3}\le x<4\\ \left[x\right],& 4\le x<5\\ |1-x|,& x\ge 5\end{array}$, where $\left[x\right]$ is the greatest integer $\le x$
The number of points of discontinuity of $f\left(x\right)$ in $R$ is

• A. 3
• B. 0
• C. infinite
• D. 1

Answer 1

The correct option is D 1

Graph of $f\left(x\right)$ can be given as above.

So, the number of points of discontinuity is $1$.