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Question

Let f(x)=∣ ∣ ∣sin2x2+cos2xcos2x2+sin2xcos2xcos2xsin2xcos2x1+cos2x∣ ∣ ∣, x[0,π].Then the maximum value of f(x) is equal to

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Solution

Given: f(x)=∣ ∣ ∣sin2x2+cos2xcos2x2+sin2xcos2xcos2xsin2xcos2x1+cos2x∣ ∣ ∣
R2R2R1
R3R3R1
f(x)=∣ ∣ ∣sin2x2+cos2xcos2x220021∣ ∣ ∣
f(x)=2sin2x+42cos2x+4cos2x
f(x)=2cos2x+4
f(x)max=6

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