Let f(x)=1+x1−x. If A is matrix for which A3=O, then f(A) is
A
I+A+A2
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B
I+2A+2A2
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C
I−A−A2
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D
O
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Solution
The correct option is BI+2A+2A2 Given: A3=O,f(x)=1+x1−x
Replacing x with A in the given expression and on cross multiplying, we have: (I−A)f(A)=I+A⇒f(A)=(I−A)−1(I+A)
We know, (I−A)−1=I+A+A2+A3+...
But we have A3=O ⇒f(A)=(I+A+A2)(1+A)=I+2A+2A2