Question

Let $f\left(x\right)=\frac{4^x}{4^x+1}$ then the value of $f\left(x\right)+f(-x)=$

• A. $0$
• B. $1$
• C. $2$
• D. none of these

Answer 1

Answer: (B)

$1$

Given,

$f\left(x\right)=\frac{4^x}{4^x+1}$.

Now,

$f\left(x\right)+f(-x)$

$=\frac{4^x}{4^x+1}$$+\frac{4^{-x}}{4^{-x}+1}$

$=\frac{4^x}{4^x+1}$$+\frac{1}{4^x+1}$

$=\frac{4^x+1}{1+4^x}$

$=1$.