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Question

Let f(x)=x1x and a be a real number, if x0=a, x1=f(x0), x2=f(x1),x3=f(x2)...
If x2009=1, then the value of a is

A
0
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B
20092010
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C
12009
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D
12010
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Solution

The correct option is D 12010
x1=f(x0)=a1a
x2=f(x1)=x11x1=a12a
x3=f(x2)=x21x2=a13a...
x2009=f(x2009)=x20091x2009=a12009a=1
a=12010

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