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Question

Let f(x) = 7esin2xecos2x+2, then the value of 7fmin+fmax, is________

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Solution

f(t)=7tet+2 for t[1,e], where t=esin2x
f(t)=7+et2>0tR
Hence f is increasing function.
fmin=f(1)=7e+2=9e
and fmax=f(e)=7e1+2=7e+1
Hence answer is 8.

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