Let fx-1-sin xsin 2x- x-2- If fx is continuous at x-2- find f-2-

The correct option is D 0 By L Hospital's Rule, =lim_x→π2 cos x2cos2x =0 2 =0 ...

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Continuity of a Function

Let fx=1-si...

Question

Let $f (x) = \frac{1 - sin x}{sin 2 x}, x \neq \frac{π}{2}$ . If $f (x)$ is continuous at $x = \frac{π}{2}$ , find $f (\frac{π}{2})$ .

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\frac{1}{2}

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Solution

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Similar questions

f (x) = \frac{1 - sin x}{sin 2 x}, x \neq \frac{π}{2}

x = \frac{π}{2},

f (\frac{π}{2})

f (x) = \frac{\sqrt{2} - \sqrt{1 + s i n x}}{c o s x}

x \neq π / 2

x = π / 2

f (π / 2)

f (x) = {(sin x)}^{\frac{1}{π - 2 x}}, x \neq \frac{π}{2}

f (x)

x = \frac{π}{2}

f (\frac{π}{2})

f (x) = \frac{1 - tan x}{4 x - π}

x \neq π / 4

x \in [0, \frac{π}{2}]

f (x)

[0, \frac{π}{2}]

f (\frac{π}{4})

x = π

f (x) = \frac{\sqrt{2 + c o s x - 1}}{(π - x^{2})}

x \neq π

f (π)

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