Let f x-1x1-tdt then f e equals

The correct option is A 1 Given, f (x)=∫_1^x1/tdt or, f(x)=log x .Now f(e)=log e=1 . ...

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Let f x=∫1x...

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Let $f (x) = \int_{1}^{x} \frac{1}{t} d t$ then $f (e)$ equals

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Similar questions

F (x) = f (x) + f (\frac{1}{x})

f (x) = \int_{1}^{x} \frac{log t}{1 + t} d t

F (e)

f (\frac{1}{x}), f (x) = \int_{1}^{x} \frac{l o g t}{1 + t} d t .

F (x) = f (x) + f (\frac{1}{x})

f (x) = \int_{1}^{x} \frac{log t}{1 + t} d t

F (e)

F (x) = f (x) + f (\frac{1}{x}),

f (x) = \int_{1}^{x} \frac{log t}{1 + t} d t .

F (e)

f (\frac{1}{x})

\int_{1}^{x} \frac{l o g t}{1 + t} d t

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