CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Let f(x)=1cos2(x3)x3,x3k,x=3, for f(x) to be continuous at x = 3, the value of k

माना f(x)=1cos2(x3)x3,x3k,x=3 है, तब x = 3 पर f(x) सतत होने के लिए k का मान

A
Exists and is equal to 2

विद्यमान है तथा इसका मान 2 है
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
Exists and is equal to 2

विद्यमान है तथा इसका मान 2 है
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
Does not exist because L.H.L is not equal to R.H.L

विद्यमान नहीं है क्योंकि L.H.L का मान R.H.L के बराबर नहीं है
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
Does not exist because L.H.L is not finite

विद्यमान नहीं है क्योंकि L.H.L परिमित नहीं है
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C Does not exist because L.H.L is not equal to R.H.L

विद्यमान नहीं है क्योंकि L.H.L का मान R.H.L के बराबर नहीं है
Solutions

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon