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Question

Let f(x)={x+2,0x<26x,x2 and g(x)={1+tanx,0x<π/43cotx,π/4x<π

Define h(x) by h(x)=f(g(x))

List IList II(I)If h(x) is continuous but not differentiable at x=aπb,(P)2where a,b are co-prime, then a+b is(II)Number of points of non-differentiability of |h(x)| is (Q)5(III)If range of h(x) is (,k], then the value of k is (R)1(IV)The value of h′′(x) at x=π/4 is 4m. Then m is (S)4

Which of the following is CORRECT combination?

A
(I)(Q), (II)(P), (III)(R), (IV)(S)
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B
(I)(S), (II)(Q), (III)(R), (IV)(P)
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C
(I)(P), (II)(Q), (III)(R), (IV)(S)
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D
(I)(Q), (II)(P), (III)(S), (IV)(R)
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Solution

The correct option is D (I)(Q), (II)(P), (III)(S), (IV)(R)
f(x)={x+2,0x<26x,x2

and g(x)={1+tanx,0x<π/43cotx,π/4x<π


f(g(x))={3+tanx,0x<π/43+cotx,π/4x<π


|h(x)|=|f(g(x))|


From above graph,
h(x) is continuous but not differentiable at x=π/4
Also, |h(x)| is not differentiable at two points.

Range of h(x) is (,4]

h′′(x) at x=π/4 is 2×sec2x×tanx=4

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