Let f(x)=ln(1+x)−x,x>0. Then which of the following is correct
A
f(x)>0
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B
f(x)≥0
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C
f(x)<0
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D
f(x)≤0
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Solution
The correct option is Cf(x)<0 Given : f(x)=ln(1+x)−x,x>0.
Differentiating the above w.r.t. x ⇒f′(x)=11+x−1=−x1+x ⇒f′(x)<0∀x>0 ∴f(x) is monotonically decreasing.
and f(0)=0
Since x>0⇒f(x)<f(0) ∴f(x)<0