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Question

Let f(x)=lnxx+1 for x>0, then which of the following is/are true :

A
f(x) has a maxima at x=1
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B
f(x) has a minima at x=1
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C
f(x)0
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D
f(x)0
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Solution

The correct option is C f(x)0
Let f(x)=lnxx+1;x(0,)
f(x)=1x1
The derivatitve is positive for 0<x<1 and negative for x>1.
Hence, function has maximum at the point x=1 i.e.
f(1)=ln11+1=0
Thus for x>0
f(x)0

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