Let f(x)=lnx−x+1for x>0, then which of the following is/are true :
A
f(x) has a maxima at x=1
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B
f(x) has a minima at x=1
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C
f(x)≤0
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D
f(x)≥0
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Solution
The correct option is Cf(x)≤0 Let f(x)=lnx−x+1;x∈(0,∞) ⇒f′(x)=1x−1
The derivatitve is positive for 0<x<1 and negative for x>1.
Hence, function has maximum at the point x=1 i.e. ⇒f(1)=ln1−1+1=0
Thus for x>0 ⇒f(x)≤0