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Question

Let f(x)=log(log1/3(log7(sinx+a))) be defined for every value of x, then the possible value of a is

A
3
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B
4
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C
5
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D
6
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Solution

The correct option is C 5
log1/3(log7(sinx+a))>0
0<log7(sinx+a)<1
1<sinx+a<7, xR
1sinx<a<7sinx
This means a should lie in between the maximum value of (1sinx) and the minimum value of (7sinx)
2<a<6

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