Let f(x)=log(log1/3(log7(sinx+a))) be defined for every value of x, then the possible value of a is
A
3
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B
4
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C
5
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D
6
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Solution
The correct option is C5 log1/3(log7(sinx+a))>0 ⇒0<log7(sinx+a)<1 ⇒1<sinx+a<7,∀x∈R ⇒1−sinx<a<7−sinx
This means a should lie in between the maximum value of (1−sinx) and the minimum value of (7−sinx) ∴2<a<6