Let f(x) = loge {u(x)v(x)}, u’(2) = 4, v’(2) = 2, u(2) = 2, v(2) = 1, then f’(2) is equal to
f(x)=2x2+bx+c and f(0)=3 and f(2)=1, then f(1) is equal to