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Question

Let f(x) = loge {u(x)v(x)}, u’(2) = 4, v’(2) = 2, u(2) = 2, v(2) = 1, then f’(2) is equal to

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Solution

f(x)=loge{u(x)v(x)}=logeu(x)logev(x)f(x)=u(x)u(u)v(x)v(x)f(2)=u(2)u(2)v(2)v(2)=4221=22=0

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