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Question

Let f(x)=⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪1sin3x3cos2x,ifx<π2a,ifx=π2b(1sinx)(π2x)2,ifx>π2. If f(x) is continuous at x=π2, find a and b.

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Solution

limxπ2f(x)=f(π2)=limxπ2+f(x)
limxπ21sin3x3cos2x=a
limxπ2(1sinx)(1+sin2x+sinx)3(1sinx)(1+sinx)=a
a=33(1+1)
a=12
limxπ2+b(1sinx)(π2x)2=a
By L - H
=limxπ2+bcosx2(π2x)(2)=a
By L - H
limx+π2+b4(sinx)2=a
b4.12=12
b=4
a=12,b=4

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