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Question

Let f(x)=sec1[1+cos2x], where [.] denotes the greatest integer function, then the range of f(x) is

A
[1, 2]
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B
[0, 2]
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C
[sec11,sec12]
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D
None of these
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Solution

The correct option is C [sec11,sec12]
f(x)=sec1{1+cos2x}0cos2x10+11+cos2x1+111+cos2x2
[1+cos2x]=1 ([] is the greatest integer function)
(for 1(1+cos2x)<2)
[1+cos2x]=2
(for(1+cos2x)=2)
the values of
y=sec1[1+cos2x]aresec11 and sec12


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