Let f(x)=sin−1|sinx|+cos−1(cosx),x∈R. Which of the following statements is/are TRUE?
A
f(f(3))=π
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B
f(x) is periodic with fundamental period 2π.
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C
f(x) is neither even nor odd.
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D
Range of f(x) is [0,2π].
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Solution
The correct option is Bf(x) is periodic with fundamental period 2π. f(x)=sin−1|sinx|+cos−1(cosx)
Clearly, f(x) is periodic function with fundamental period 2π.
So, we calculate f in [0,2π] f(x)=⎧⎪
⎪
⎪
⎪
⎪
⎪⎨⎪
⎪
⎪
⎪
⎪
⎪⎩2x,0≤x≤π2π,π2<x≤3π24π−2x,3π2<x≤2π