Let f(x)=sin4x+cos4x. Then f is an increasing function in the interval :
A
[0,π4]
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B
[π4,π2]
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C
[π2,5π4]
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D
[5π5,3π4]
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Solution
The correct option is B[π4,π2] f(x)=sin4x+cos4xf′(x)=4sin3x(cosx)+4cos3x(−sinx)=4sinxcosx(sin2x−cos2x)=−sin4x⇒f(x) is increasing when f′(x)>0⇒sin4x<0⇒x∈(π4,π2)∴ option B is correct.