Let f(x)=sin4x+cos4x. Then f is an increasing function in the interval :
A
[5π8,3π4]
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B
[π2,5π8]
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C
[0,π4]
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D
[π4,π2]
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Solution
The correct option is D[π4,π2] f(x)=sin4x+cos4xf′(x)=4sin3xcosx−4cos3xsinx=4sinxcosx(sin2x−cos2x)=−2sin2x.cos2x=−sin4xf′(x)≥0(for increasing function)⇒sin4x≤0⇒π≤4x≤2π x∈[π4,π2]