Let fx-sin x-0- x - 2- then

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Local Maxima

Let fx=|sin...

Question

Let $f (x) = | sin x |, 0 \leq x \leq 2 π$ then

f (x)

is differentiable at infinite number of points

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f (x)

is non-differentiable at 3 points

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f (x)

is continuous everywhere

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f (x)

is discontinuous at 3 points

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Solution

The correct options are
B $f (x)$ is non-differentiable at 3 points
C $f (x)$ is continuous everywhere
From the graph of $| sin x |$ , it is clear that $f$ is continuous everywhere and it has three sharp points at $x = 0, π, 2 π$ .
Therefore, it is not differentiable at 3 points

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Let f(x)=|sinx|,0≤x≤2π then

The correct options are B f(x) is non-differentiable at 3 points C f(x) is continuous everywhereFrom the graph of |sinx|, it is clear that f is continuous everywhere and it has three sharp points at x=0,π,2π.Therefore, it is not differentiable at 3 points

Let $f (x) = | sin x |, 0 \leq x \leq 2 π$ then

The correct options are
B $f (x)$ is non-differentiable at 3 points
C $f (x)$ is continuous everywhere
From the graph of $| sin x |$ , it is clear that $f$ is continuous everywhere and it has three sharp points at $x = 0, π, 2 π$ .
Therefore, it is not differentiable at 3 points