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Chain Rule of Differentiation

Let fx = ta...

Question

Let $f (x) = tan 2 x . tan 3 x . tan 5 x t h e n, f^{'} (π)$ equals

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Solution

$f^{'} (x) = 2 s e c^{2} (2 x) . t a n (3 x) . t a n (5 x) + 3 s e c^{2} (3 x) . t a n (2 x) . t a n (5 x) + 5 s e c^{2} (5 x) . t a n (2 x) . t a n (3 x)$
$f^{'} (π) = 2.1.0.0 + 3.0.1.0 + 5.0.0.1$
$= 0$

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