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Question

Let f(x)=(x+1)21,(x1). Then the set S={x:f(x)=f1(x)}. is

A
Empty
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B
{0,1}
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C
{0,1,1}
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D
{0,1,3+i32,3i32}
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Solution

The correct option is D {0,1,3+i32,3i32}
Letf(x)=(x+1)21,x1.Since f(x)=f1(x)(x+1)21=1+x1(f1(x)=1+x1)(x+1)4=1+x(x+1)[(x+1)31]=0x=1 or(x+1)3=1x+1=1,ω,ω2x=0,1,3+i32,3i32

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