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Question

Let f(x)=x212x10. Then

A
domain of f is R
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B
domain of f is R{6}
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C
range of f is R
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D
range of f is [46,)
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Solution

The correct option is D range of f is [46,)
f(x)=x212x10
f(x)=(x6)246
Clearly, f is defined for all real values of x
Hence, domain =R

0(x6)2<
46(x6)246<
Hence, range of f is [46,)

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