Let , f(x)=x2+5x+6, then the number of real roots of (f(x))2+5f(x)+6−x=0 is
1
2
3
0
Use “f(x) = x has non real roots ⇒ f(f(x)) = x also has non-real roots”
The number of real solutions of the equation x2+3|x|+2 =0 is: