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Question

Let f(x)=x2 and g(x)=2x+1 be two real functions.Find (f+g)(x),(fg)(x),(fg)(x),fg(x).

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Solution

Given: f(x)=x2 and g(x)=2x+1
Step 1:Addition of two functions
(f+g)(x)=f(x)+g(x) =x2+(2x+1) =x2+2x+1

Step 2:Subtraction of two functions
(fg)(x)=f(x)g(x)
=x2(2x+1)
=x22x1

Step 3: Multiplication of two functions
(fg)(x)=f(x).g(x)
=x2(2x+1)
=2x3+x2

Step 4:Division of two functions
fg(x)=f(x)g(x)=x22x+1
As denominator cannot be zero fg(x)=x22x+1,x12

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