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Question

Let f(x)=x2 and g(x)=3x+4. Find the value of (f+g)(x)(fg)(x) when x=1


A

43

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B

34

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C

43

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D

34

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Solution

The correct option is C

43


(f+g)(x)=f(x)+g(x)=x2+3x+4(fg)(x)=f(x)g(x)=x23x4(f+x)(x)(fg)(x)=x2+3x+4x23x4To find (f+g)(x)(fg)(x)at x=1,put x=11+3+4134=86=43

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