wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Let f(x)=x2 and g(x)=3x+4. Find the value of (f+g)(x)(fg)(x) when x=1


A

43

No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

34

No worries! We‘ve got your back. Try BYJU‘S free classes today!
C

43

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D

34

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C

43


(f+g)(x)=f(x)+g(x)=x2+3x+4(fg)(x)=f(x)g(x)=x23x4(f+x)(x)(fg)(x)=x2+3x+4x23x4To find (f+g)(x)(fg)(x)at x=1,put x=11+3+4134=86=43

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Some Functions and Their Graphs
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon