Let,f(x)=x2and g(x)=3x+4.Find the value of (f+g)(x)(f−g)(x) when x = 1
(f+g)(x)=f(x)+g(x)=x2+3x+4(f−g)(x)=f(x)−g(x)=x2−3x−4⇒(f+x)(x)(f−g)(x)=x2+3x+4x2−3x−4To find,(f+g)(x)(f−g)(x)at x=1,put x=1⇒1+3+41−3−4=8−6=−43
Let f(x) = x2 and g(x) = 3x + 4 . Find the value of (f+g)(x)(f−g)(x) when x = 1
Let f(x)=x2 and g(x)=3x+4. Find the value of (f+g)(x)(f−g)(x) when x=1
Let f and g be real functions, defined by f(x)=√x+2 and g(x)=√4−x2. Find
(i) (f+g)(x)
(ii) (f−g)(x)
(iii) (fg)(x)
(iv) (ff)(x)
(v) (gg)(x)
(vi) (fg)(x)