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Question

Let,f(x)=x2and g(x)=3x+4.Find the value of (f+g)(x)(fg)(x) when x = 1


A

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B

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C

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Solution

The correct option is C


(f+g)(x)=f(x)+g(x)=x2+3x+4(fg)(x)=f(x)g(x)=x23x4(f+x)(x)(fg)(x)=x2+3x+4x23x4To find,(f+g)(x)(fg)(x)at x=1,put x=11+3+4134=86=43


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