Let- fx-x2 and gx-3 x-4-Find the value of f-gx-f-gx when x-1A- 4-3B- 3-4C- -4-33D- -3-4

The correct option is C (f+g)(x)=f(x)+g(x)=x^2+3x+4 (f g)(x)=f(x) g(x)=x^2 3x 4 ⇒(f+x)(x)/(f g)(x)=x^2+3x+4/x^2 3x 4 To find,(f+g)(x)/(f g)(x)at x=1,put x=1 ...

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Byju's Answer

Standard VIII

Mathematics

Rational function

Let, fx=x2 an...

Question

Let, $f (x) = x^{2} a n d g (x) = 3 x + 4$ .Find the value of $\frac{(f + g) (x)}{(f - g) (x)}$ when x = 1

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Solution

The correct option is C

$(f + g) (x) = f (x) + g (x) = x^{2} + 3 x + 4 (f - g) (x) = f (x) - g (x) = x^{2} - 3 x - 4 \Rightarrow \frac{(f + x) (x)}{(f - g) (x)} = \frac{x^{2} + 3 x + 4}{x^{2} - 3 x - 4} To find, \frac{(f + g) (x)}{(f - g) (x)} a t x = 1, put x = 1 \Rightarrow \frac{1 + 3 + 4}{1 - 3 - 4} = \frac{8}{- 6} = \frac{- 4}{3}$

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Let f(x) = $x^{2}$ and g(x) = 3x + 4 . Find the value of $\frac{(f + g) (x)}{(f - g) (x)}$ when x = 1

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Let,f(x)=x2and g(x)=3x+4.Find the value of (f+g)(x)(f−g)(x) when x = 1

The correct option is C (f+g)(x)=f(x)+g(x)=x2+3x+4(f−g)(x)=f(x)−g(x)=x2−3x−4⇒(f+x)(x)(f−g)(x)=x2+3x+4x2−3x−4To find,(f+g)(x)(f−g)(x)at x=1,put x=1⇒1+3+41−3−4=8−6=−43

Let, $f (x) = x^{2} a n d g (x) = 3 x + 4$ .Find the value of $\frac{(f + g) (x)}{(f - g) (x)}$ when x = 1