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Byju's Answer
Standard XII
Mathematics
Bijective Function
Let fx= x+2 a...
Question
Let
f
(
x
)
=
x
+
2
and
g
(
x
)
=
c
x
+
d
,
c
≠
0
. If
(
f
o
g
)
(
x
)
=
(
g
o
f
)
(
x
)
for all
x
,
then
c
is
A
1
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B
01
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C
1.0
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D
1.00
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Solution
(
f
o
g
)
(
x
)
=
f
(
g
(
x
)
)
=
(
c
x
+
d
)
+
2
and
(
g
o
f
)
(
x
)
=
g
(
f
(
x
)
)
=
c
(
x
+
2
)
+
d
Given that
(
f
o
g
)
(
x
)
=
(
g
o
f
)
(
x
)
⇒
c
x
+
d
+
2
=
c
x
+
2
c
+
d
⇒
c
=
1
and
d
is any arbitrary constant.
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0
Similar questions
Q.
Let
f
x
=
x
2
and
g
x
=
2
x
. Then, the solution set of the equation
f
o
g
x
=
g
o
f
x
is
(a) R
(b) {0}
(c) {0, 2}
(d) none of these
Q.
Find fog and gof if
(i)
f
x
=
e
x
,
g
x
=
log
e
x
(ii)
f
x
=
x
2
,
g
x
=
cos
x
(iii)
f
x
=
|
x
|
,
g
(
x
)
=
sin
x
(iv)
f
x
=
x
+
1
,
g
x
=
e
x
(v)
f
x
=
sin
-
1
x
,
g
x
=
x
2
(vi)
f
x
=
x
+
1
,
g
x
=
sin
x
(vii)
f
x
=
x
+
1
,
g
x
=
2
x
+
3
(viii)
f
x
=
c
,
c
∈
R
,
g
x
=
sin
x
2
(ix)
f
x
=
x
2
+
2
,
g
x
=
1
-
1
1
-
x
Q.
Let
f
x
=
α
x
x
+
1
,
x
≠
-
1
. Then, for what value of α is
f
f
x
=
x
?
(a)
2
(b)
-
2
(c) 1
(d) −1
Q.
Let g (x),
x
≥
0
, be a non-negative continuous function and let
F
(
x
)
=
∫
x
0
f
(
t
)
d
t
,
x
≥
0
. If for some c > 0, f(x)
≤
c F(x) for all
x
≥
0
, then
Q.
If
g
f
x
=
sin
x
and
f
g
x
=
sin
x
2
,
then
(a)
f
x
=
sin
2
x
,
g
x
=
x
(b)
f
x
=
sin
x
,
g
x
=
|
x
|
(c)
f
x
=
x
2
,
g
x
=
sin
x
(d) f and g cannot be determined.
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Bijective Function
Standard XII Mathematics
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