Let f x - x -2- x -3- x -4- and g x - f x -1- Then-A- g x is neither even nor oddB- None of theseC- gx is an even functionD- gx is an odd function

The correct option is A g(x) is neither even nor oddg(x) = f(x + 1) = |x 2 + 1| + |x 3 + 1| + |x 4 + 1| = |x 1| + |x 2| + |x 3| ...

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Quantitative Aptitude

Functions

Let f x =| x ...

Question

Let f(x) = |x - 2| + |x - 3| + |x - 4| and g(x) = f(x + 1). Then?

g(x) is an even function

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g(x) is an odd function

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g(x) is neither even nor odd

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None of these

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Solution

The correct option is C g(x) is neither even nor odd
g(x) = f(x + 1) = |x - 2 + 1| + |x - 3 + 1| + |x - 4 + 1|
= |x - 1| + |x - 2| + |x - 3|

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Let f(x) = |x - 2| + |x - 3| + |x - 4| and g(x) = f(x + 1). Then?

The correct option is C g(x) is neither even nor oddg(x) = f(x + 1) = |x - 2 + 1| + |x - 3 + 1| + |x - 4 + 1| = |x - 1| + |x - 2| + |x - 3|

The correct option is C g(x) is neither even nor odd
g(x) = f(x + 1) = |x - 2 + 1| + |x - 3 + 1| + |x - 4 + 1|
= |x - 1| + |x - 2| + |x - 3|