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Question

Let f(x)=x312x2+ax+b is an increasing function and f(3)=3,f(4)=4 the

A
a=48
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B
b=38
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C
a=48
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D
b=38
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Solution

The correct option is A a=48
Given f(x)=x312x2+ax+b.
Also given,
f(3)=3
or, 27108+3a+b=3
or, 3a+b=84.......(1).
Also f(4)=4
or, 64192+4a+b=4
or, 4a+b=132......(2).
Now, subtracting (1) from (2) we get,
a=48.
Putting the value of a in (1) we get,
b=60.

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