Let f(x)=x3−x2+1 be a continuous function in R.
Statement 1:f(x) has atleast one real solution in (−2,2).
Statement 2:f−1(x) has atleast one real solution in (−2,2).
Then
A
Statement 1 is true, Statement 2 is true and Statement 2 is the correct explanation of Statement 1.
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B
Statement 1 is true, Statement 2 is true and Statement 2 is not the correct explanation of Statement 1.
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C
Statement 1 is true and Statement 2 is false.
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D
Statement 1 is false and Statement 2 is true.
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Solution
The correct option is C Statement 1 is true and Statement 2 is false. Given : f(x)=x3−x2+1 is continuous in [−2,2] ⇒f(−2)<0 and f(2)>0 ⇒f(x)=0 has atleast one solution in (−2,2).
Also, f(x) is not invertible as f(0)=f(1)=1 which is not one-one.