Let f(x)=(x+3)(x−3) for any value of x. Calculate the least possible value of f(x).
A
−9
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B
−3
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C
0
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D
3
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E
9
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Solution
The correct option is A−9 As given f(x)=(x+3)(x−3) By using (a+b)(a−b)=a2−b2 ⇒(x+3)(x−3)=x2−32=x2−9 Since, f(x)=x2−9 and the least possible value of x2 is zero. then the least possible value of f(x) is 0−9=−9. Hence, option A is correct.