MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Quantitative Aptitude

Functions

Let fx=x4+y4-...

Question

Let $f (x) = x^{4} + y^{4} - x^{3} y^{2} - x^{2} y^{3} + 16 x y$ . If x+y=2, what is the value of f(x)?

A

10

No worries! We‘ve got your back. Try BYJU‘S free classes today!

B

8

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C

16

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

D

12

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C 16
Option (c) is the correct answer. Check the video for the approach.

Suggest Corrections

thumbs-up

0

Similar questions

f (x) = (x^{12} - x^{9} + x^{4} - x + 1)^{- 1 / 2}

. Then domain of function

f (x)

f : [- 1, 1] \to R,

f (x) = 2 x^{3} - x^{4} - 10.

The minimum value of

f (x)

Q. Find the value of

f (x) = x^{4} + 3 x^{3} + 2 x^{2} + 1

x = 2

f (x, y) = x y^{2}

x

y

x^{2} + y^{2} = 9

then the minimum value of

f (x, y)

f (x) = ⎧ ⎪ ⎪ ⎪ ⎨ ⎪ ⎪ ⎪ ⎩ \begin{matrix} \begin{matrix} \frac{x^{4} - 5 x^{2} + 4}{(x - 1) (x - 2)}, & x \neq 1, 2 \end{matrix} \begin{matrix} 6, & x = 1 \end{matrix} \begin{matrix} 12, & x = 2 \end{matrix} \end{matrix}

f (x)

is continuous on the set

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Functions

QUANTITATIVE APTITUDE

Watch in App

explore_more_icon

Explore more

Other Quantitative Aptitude

Join BYJU'S Learning Program

CrossIcon