Let f(x) = x + sin x. The area bounded by y=f−1(x),y=x,xϵ[0,π] is
1
2
3
cannot be found because f−1(x) cannot be determined
The curves given by y = x + sin x and y=f−1(x) are images of each other in the line y = x. Hence required area =∫π0((x+sinx)−x)dx=−[cosx]π0=2