CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Let f(x,y)=x2+y2+x2+y22x+1+x2+y22y+1+x2+y26x8y+25x,yϵR, then


A

Minimum value of f(x, y) = 5 + 2

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B

Minimum value of f(x, y) = 5 - 2

No worries! We‘ve got your back. Try BYJU‘S free classes today!
C

Minimum value occurs of f(x, y) for x =37

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D

Minimum value occurs of f(x, y) for y =47

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct options are
A

Minimum value of f(x, y) = 5 + 2


C

Minimum value occurs of f(x, y) for x =37


D

Minimum value occurs of f(x, y) for y =47


Let O(0, 0), A = (1, 0), B = (3, 4), C = (0, 1)
Now for (x, y) to be minimum, (x, y) must be the point of intersection of OB and AC

f(x, y)min=OB+AC=5+2
which occurs at
x=37, y=47


flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Factorisation and Rationalisation
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon