Let f(x,y)=√x2+y2+√x2+y2−2x+1+√x2+y2−2y+1+√x2+y2−6x−8y+25∀x,yϵR, then
Minimum value of f(x, y) = 5 + √2
Minimum value occurs of f(x, y) for x =37
Minimum value occurs of f(x, y) for y =47
Let O(0, 0), A = (1, 0), B = (3, 4), C = (0, 1)
Now for (x, y) to be minimum, (x, y) must be the point of intersection of OB and AC
∴ f(x, y)min=OB+AC=5+√2
which occurs at
x=37, y=47