Let five letter words be formed using the letters of the word REPETITIVE. Then total number of words with exactly two pairs of alike letters is

720

No worries! We‘ve got your back. Try BYJU‘S free classes today!

120

No worries! We‘ve got your back. Try BYJU‘S free classes today!

270

No worries! We‘ve got your back. Try BYJU‘S free classes today!

360

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $360$
$R E P E T I T I V E$
$\to (E E E), (T T), (I I), (R P V)$

Total words that can be formed when exactly two letters are repeated once $=^{3} C_{2} \times^{4} C_{1} \times \frac{5!}{2! 2!} = 360$

Suggest Corrections

Similar questions

Q. The number of

9

lettered words that can be formed using all the letters of the word 'MEENANSHU' if alike letters are never adjacent, is

k (7!)

. Then

^{'} k^{'}

lies in the interval:

Q. The number of words can be formed using all letters of the word EQUATION, using each letter exactly once is

Q. Number of

4

-lettered words, with or without meaning, that can be formed using letters in the word

^{'} L O G A R I T H M S^{'}

, if repetition of letters is not allowed is

Q. Number of

4

-lettered words, with or without meaning, that can be formed using letters in the word

^{'} L O G A R I T H M S^{'}

, if repetition of letters is not allowed is

The number of words, with or without meaning, that can be formed by taking $4$ letters at a time from the letters of the word $^{'} {SYLLABUS}^{'}$ such that two letters are distinct and two letters are alike, is

Join BYJU'S Learning Program

Let five letter words be formed using the letters of the word REPETITIVE. Then total number of words with exactly two pairs of alike letters is

The correct option is D 360REPETITIVE →(EEE),(TT),(II),(RPV) Total words that can be formed when exactly two letters are repeated once =3C2×4C1×5!2! 2!=360

The correct option is D $360$
$R E P E T I T I V E$
$\to (E E E), (T T), (I I), (R P V)$

Total words that can be formed when exactly two letters are repeated once $=^{3} C_{2} \times^{4} C_{1} \times \frac{5!}{2! 2!} = 360$