Let G be the centroid of ABC- If AB-a and AC-b- then AG- in terms of a and b is

The correct option is D #160; 1 3 ( a + b #160;) Let A be the origin.then AB = a , AC = b implies that the position vectors of B ...

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Equation of a Line Passing through 2 Points

Let G be th...

Question

Let $G$ be the centroid of $△ A B C$ . If $- - \to A B = \to a$ and $- - \to A C = \to b,$ then $- - \to A G$ , in terms of $\to a$ and $\to b$ is

\frac{2}{3} (\to a + \to b)

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\frac{1}{6} (\to a + \to b)

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\frac{1}{3} (\to a + \to b)

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\frac{1}{2} (\to a + \to b)

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Similar questions

G

A B C

A B = a, A C = b

A G

a

b

\vec{A B} = \vec{a,} \vec{A C} = \vec{b,}

\vec{A G},

\vec{a} and \vec{b}

\frac{2}{3} (\vec{a} + \vec{b})

\frac{1}{6} (\vec{a} + \vec{b})

\frac{1}{3} (\vec{a} + \vec{b})

\frac{1}{2} (\vec{a} + \vec{b})

∠ 1 = (2 a + b)^{\circ} a n d ∠ 6 = (3 a - b)^{\circ}

∠ 2

X = 1 + 3 a + 6 a^{2} + 10 a^{3} + . . . ., | a | < 1

y = 1 + 4 b + 10 b^{2} + 20 b^{3} + . . . ., | b | < 1

(a^{3} (a - 1), a^{2} - 3 (a - 1)), (b^{3} (b - 1), b^{2} - 3 (b - 1))

(\frac{c^{3}}{(} c - 1), c^{2} - 3 (c - 1))

a, b, c

a \neq 1, b \neq 1

c \neq 1

a b c - (a b + b c + a c) + 3 (a + b + c)

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