The grammar is
S→ aSb | SS|
ϵ
(a) G is not ambiguous is false,since
ϵ which belongs to L(G),has infinite number of dervation trees,which makes G ambiguous.Some derivation trees are given below
(b) There exists x,y
ϵ L(G) such that xy
/ϵ L(G) is false,since
S→ SS can be used to denotes xy, whenever x
ϵ L(G) and y
ϵ L(G)
(c) is true since this language is L(G)={w |
na(w)=nb(w) and
na(v)≥nb(v) where v is any prefix of w} which is equal to (
anbn)∗
This language happens to be a deteministic context free language.
∴ There exists a DPDA that accepts it.
(d) is false, as the given language is not regular (comparison between number of 'a' s and number of 'b' is there).
∴ No DFA exists to accept it.