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Question

Let g(x) be an antiderivative for f(x). Then In (1+(g(x))2) is an antiderivate for

A
2f(x)g(x)1+(f(x))2
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B
2f(x)g(x)1+(g(x))2
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C
2f(x)1+(f(x))2
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D
None
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Solution

The correct option is B 2f(x)g(x)1+(g(x))2
Given f(x)dx=g(x)g(x)=f(x)
Now ddx(In(1+g2(x))=2g(x)g(x)1+g2(x)2f(x)g(x)1+g2(x)

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