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Quantitative Aptitude

Functions

Let gx=max 2 ...

Question

Let g(x) = max (2x+1, 3-4x) where 'x' is a real number. Find the minimum possible value of g(x).

A

\frac{1}{3}

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B

\frac{1}{2}

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C

\frac{2}{3}

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D

\frac{5}{3}

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Solution

The correct option is D $\frac{5}{3}$
Option (d) is the correct answer. Check the video for the approach.

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