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Byju's Answer
Standard XII
Mathematics
Monotonically Increasing Functions
Let hx = fx...
Question
Let
h
(
x
)
=
f
(
x
)
−
(
f
(
x
)
)
2
+
(
f
(
x
)
)
3
for every real number
x
, then
A
h
is increasing whenever
f
is increasing and decreasing whenever
f
is decreasing
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B
h
is increasing whenever
f
is decreasing
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C
h
is decreasing whenever
f
is increasing
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D
Nothing can be said in general
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Solution
The correct option is
A
h
is increasing whenever
f
is increasing and decreasing whenever
f
is decreasing
h
(
x
)
=
f
(
x
)
−
(
f
(
x
)
)
2
+
(
f
(
x
)
)
3
When
x
=
2
h
(
x
)
=
2
−
2
2
+
2
3
=
6
When
x
=
−
2
h
(
x
)
=
−
2
−
(
−
2
)
2
+
(
−
2
)
3
=
−
14
Therefore, h is increasing whenever f is increasing and decreasing whenever f is decreasing.
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0
Similar questions
Q.
Assertion :Let
f
and
g
be increasing and decreasing functions respectively from
[
0
,
∞
]
to
[
0
,
∞
]
. Let
h
(
x
)
=
f
(
g
(
x
)
)
. If
h
(
0
)
=
0
,
then
h
(
x
)
is always zero Reason:
h
(
x
)
is an increasing function of
x
Q.
Let
h
(
x
)
=
f
(
x
)
−
a
(
f
(
x
)
)
2
+
a
(
f
(
x
)
)
3
for every real number
x
.
h
(
x
)
increases as
f
(
x
)
decreases for all real values of
x
if
Q.
Let
h
(
x
)
=
f
(
x
)
−
a
(
f
(
x
)
)
2
+
a
(
f
(
x
)
)
3
for every real number
x
.
h
(
x
)
increases as
f
(
x
)
increases for all real values of
x
if
Q.
Let
h
(
x
)
=
f
(
x
)
−
a
(
f
(
x
)
)
2
+
a
(
f
(
x
)
)
3
for every real number
x
.
If
f
(
x
)
is strictly increasing function, then
h
(
x
)
is non-monotonic function given
Q.
Let
f
and
g
be increasing and decreasing functions respectively from
(
0
,
∞
)
to
(
0
,
∞
)
and let
h
(
x
)
=
f
[
g
(
x
)
]
. If
h
(
0
)
=
0
then
h
(
x
)
−
h
(
1
)
is
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