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Question

Let ^a, ^b and ^c be three unit vectors such that
^a×(^b×^c)=32(^b+^c). If
^b is not parallel to ^c, then the angle between ^a and ^b is


A

3π4

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B

π2

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C

2π3

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D

5π6

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Solution

The correct option is D

5π6


Given, |^a|=|^b|=|^c|=1and ^a×(^b×^c)=32(^b+^c)
Now, consider ^a×(^b×^c)=32(^b+^c)
(^a.^c)^b(^a.^b)^c=32^b+32^c
On comparing, we get
^a.^b=32|^a||^b| cos θ=32 cos θ=32 [ |^a|=|^b|=1] cos θ=cos(ππ6)θ=5π6


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