Let I be the identity matrix and adj(X) denote the adjoint of matrix X. If A=⎡⎢⎣100101010⎤⎥⎦ satisfies An=An−2+A2−I for all n≥3, then ∣∣adj(adj(adj(A50)))∣∣ is
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Solution
An−An−2=A2−I A50−A48=A2−I A48−A46=A2−I ⋅ ⋅ ⋅ A4−A2=A2−I––––––––––––––––––––
Adding above equations, we get A50−A2=24A2−24I ⇒A50=25A2−24I