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Question

Let I=⎡⎢⎣100010001⎤⎥⎦ and P=⎡⎢⎣1000−1000−2⎤⎥⎦ Then the matrix P3+2P2 is equal to

A
P
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B
IP
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C
2IP
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D
I2P
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Solution

The correct option is C 2IP
P=100010002
P2=100010002100010002
=100010004
P2=100010004100010002
=100010008
P3+2P2=100010008200020008
=300010000
P3+2P2P,P3+2P21P
2IP=300010000=P3+2P2
Option C

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