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Question

Let I=ba(x42x2)dx. If I is minimum then the ordered pair (a,b) is :

A
(0,2)
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B
(2,0)
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C
(2,2)
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D
(2,2)
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Solution

The correct option is C (2,2)
I=ba(x42x2)dx.
y=x42x2=0
x=0,±2 (1)
Therefore, the graph of the above curve is -
Hence, from the graph we can conclude that the Integral value I is minimum when the curve is bounded between (2,0),(2,0).
Therefore, the ordered pair (a,b) is :(2,2)

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