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Byju's Answer
Standard XII
Mathematics
Multinomial Expansion
Let I n =∫01 ...
Question
Let
I
n
=
1
∫
0
x
n
x
2012
−
1
d
x
,
J
n
=
1
∫
0
x
n
x
2013
+
1
d
x
for all
n
>
2012
,
n
∈
N
and matrix
A
=
(
a
i
j
)
3
×
3
,
where
a
i
j
=
{
I
2012
+
i
−
I
i
,
i
=
j
0
,
i
≠
j
and matrix
B
=
(
b
i
j
)
3
×
3
,
where
b
i
j
=
{
J
2016
+
j
+
J
j
+
3
,
i
=
j
0
,
i
≠
j
.
Then the value of
trace
(
A
−
1
)
+
|
B
−
1
|
is
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Solution
I
2012
+
i
−
I
i
=
∫
1
0
x
i
(
x
2012
−
1
)
(
x
2012
−
1
)
d
x
=
1
1
+
i
J
2016
+
j
+
J
j
+
3
=
∫
1
0
x
j
+
3
(
x
2013
+
1
)
(
x
2013
+
1
)
d
x
=
1
j
+
4
∴
A
=
⎡
⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢
⎣
1
2
0
0
0
1
3
0
0
0
1
4
⎤
⎥ ⎥ ⎥ ⎥ ⎥ ⎥ ⎥
⎦
,
B
=
⎡
⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢
⎣
1
5
0
0
0
1
6
0
0
0
1
7
⎤
⎥ ⎥ ⎥ ⎥ ⎥ ⎥ ⎥
⎦
tr
(
A
−
1
)
+
|
B
−
1
|
=
(
2
+
3
+
4
)
+
(
5
×
6
×
7
)
=
219
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0
Similar questions
Q.
let
A
=
[
a
i
j
]
3
×
3
and
B
=
[
a
i
j
]
3
×
3
, where
b
i
j
=
2
i
+
j
a
i
j
for all
i
,
j
. if
i
,
j
.
If
|
A
|
=
2
, then
|
B
|
=
Q.
Let
J
n
,
m
=
1
/
2
∫
0
x
n
x
m
−
1
d
x
,
∀
n
>
m
and n
,
m
∈
N
.
Consider a matrix
A
=
[
a
i
j
]
3
×
3
where
a
i
j
=
{
J
6
+
i
,
3
−
J
i
+
3
,
3
i
≤
j
0
i
>
j
.
Then
|
a
d
j
A
−
1
|
is
Q.
Construct a
3
×
3
matrix whose elements
a
i
j
are given by
a
i
j
=
0
if
i
≠
j
and
a
i
j
=
−
8
if
i
=
j
.
Q.
Let
A
=
{
a
i
j
}
be a
3
×
3
matrix, where
a
i
j
=
⎧
⎪
⎨
⎪
⎩
(
−
1
)
j
−
i
if
i
<
j
,
2
if
i
=
j
,
(
−
1
)
i
+
j
if
i
>
j
,
then
det
(
3
A
d
j
(
2
A
−
1
)
)
is equal to
Q.
Let
a
>
b
>
0
and
I
(
n
)
=
a
1
/
n
–
b
1
/
n
,
J
(
n
)
=
(
a
–
b
)
1
/
n
for all
n
≥
2
. then
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