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Question

Let In=10xnx20121 dx, Jn=10xnx2013+1 dx for all n>2012, nN and matrix A=(aij)3×3, where aij={I2012+iIi, i=j 0, ij
and matrix B=(bij)3×3,
where bij={J2016+j+Jj+3, i=j 0, ij.
Then the value of trace(A1)+|B1| is

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Solution

I2012+iIi=10xi(x20121)(x20121) dx=11+i

J2016+j+Jj+3=10xj+3(x2013+1)(x2013+1) dx=1j+4

A=⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢120001300014⎥ ⎥ ⎥ ⎥ ⎥ ⎥ ⎥, B=⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢150001600017⎥ ⎥ ⎥ ⎥ ⎥ ⎥ ⎥

tr(A1)+|B1|=(2+3+4)+(5×6×7)=219

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